Tanmoy Das

When I was typing this question, my brain was hinting me in your very same point. funny. I will post here if I found something useful from lp file - Latex direction,

Hello Jaromił Najman, appreciate your explanation.  In an optimization model that I am developing right now, the objective function contains 3 terms, two of these terms would be zero depending on i...

Hello Jaromil, I will keep your suggestions in mind. I solved the conflict of C1 & C3 by changing comparison operator == into <= in C3  model1.addConstrs((cover.sum(c,'*') <= 1 for c in range(num_...

Revised formulation below: # MIP model formulationmodel1 = gp.Model('MCLP v1')# Decision variablescover = model1.addVars(pairings, vtype=GRB.BINARY, name='Cover')select = model1.addVars(num_facili...

num_facilities = len(facilities) num_customers = len(customers) cartesian_prod = list(product(range(num_customers), range(num_facilities)))

Comment outside of your question: Its better to be consistent on naming the variables e.g. all INDICES with small_loc two/few letters e.g. time, res and then associated SET with CapLock maybe. e.g....

It will be easier to think if you post your constraints math equation. Anyway,  Endresources=steel.addConstrs((gp.quicksum(Resources[res,t] for t in x )==1 for res in res_list3),name="Endresources"...

you can write the model, then print the written model (possibly in rlp or lp format) in Jupyter Lab (or whatever IDE you are using)

Appreciate your comment Matthias Miltenberger. Such thinking process of Indicator constraints is helping me building my model 

Jaromił Najman already gave a details answer. Thanks.  I just wanted to say one little point (that I keep in mind when it comes to addConstrs vs addConstr) If you see the following model, the 3rd c...