I want to convert this formula into code
Awaiting user input
help me plz..
0
-
Official comment
This post is more than two years old. Some information may not be up to date. For current information, please check the Gurobi Documentation or Knowledge Base. If you need more help, please create a new post in the community forum, or try Gurobot, our chatbot interface offering instant, expert-level support. -
Have you tried it step-by-step and where did you get stuck exactly? I would start creating a variable containing the value of the inner sum. Then try to create the max and finally the outer sum.
0 -
T = ['t1','t2','t3','t4','t5','t6','t7','t8','t9'] #index of trailer
U = ['u1','u2','u3'] #index of unload dock
B = ['b1','b2','b3'] #index of time bucket
S = ['s1','s2','s3'] #index of output_station
num_trailer = len(T)
num_unload_docks = len(U)
num_time_bucket = (len(T) // len(U))
num_output_station = len(S)Lmax = quicksum(max(quicksum(t[d, s] * x[t, b] for t in range(num_trailer) for b in range(num_time_bucket)))for s in range(num_output_station)for b in range(num_time_bucket))
Tried to convert sigma into code. Is this the right code?
0 -
- The inner quicksum seems incorrect - you reference d which is not defined anywhere.
- Then you take the max over just a single quicksum. You need multiple things to take the maximum; I guess you will need to move one of the two iterator variables/loops outside the quicksum.
- For the maximum, you cannot use the built-in Python max function since it only works for scalar values, not Gurobi variables. You will want a new, auxiliary variable that will be equal to the maximum of the inner quicksums. Have a look at the max_ function for details.
- Finally, you can sum over the auxiliary variables to get the final result.
0
Post is closed for comments.
Comments
4 comments