Ana Guasque Ortega

Thank you both very much!! I'm trying to implement it.  Best, Ana.

If I write an objective function, the behaviour is still the same. I write a simplified version of the code. In my case, there may be hundreds of solutions with the same objective function so I wan...

Thanks, Jonasz! I have a doubt. The value of solution on the above code ( or print(model.cbGetSolution(model._vars))) is always an empty list. Could it be because I have no objective function to op...

Many thanks, Jonasz, that is what I thought and the reason to ask here. Yes, please, send me a code example for the first option, only to know if I can improve something or, as you said, maybe with...

Thanks again for your great response :)

Many thanks, David! I didn't know this possibility. An another question related to indicator constraints (if I should write the question at any other thread, please tell me) I read that it is not p...

Many thanks, Jaromil, now it is totally understood.  Maybe I should consider another way of modelling the problem since each of the lists may have up to 100 values, approximatelly. Maybe it becames...

Many many thanks, Jaromil! I get the point, I think I can do it. But, what if the values are not following any sequence? How to obtain the value of v2 in that case? for example: dict={'a':[1,1,2,2,...

Hi again, Jaromil! Many thanks, it worked.  However, it does not solve my problem. Maybe I did not explain it well. What I want is to find the value of the variable. Imagine this: dict={'a':[12,24,...

Many thanks for your response, Jaromil. Could I query the values of the attributes before the optimization is complete? I have tried to see (only for checking how it works) the name of the variable...