Store optimized value into a list

Answered

nahom tsehaie

October 31, 2022 12:55

• 
• 

Hi all,

I wan to the store the objective value in a list, since I iterate the solver in a loop. I don't how to do that. 

my code: 

for i in range(10):

 

# update model, solve, return the chromatic number

    m.update()

    m.optimize()

    chrom_num = m.objVal

    print("chromatic number of this graph is ", m.objVal)

    chrom_list = []

    chrom_list.append(chrom_num)

    chrom_3 = np.asarray(chrom_list[i])

    m.reset()

    print(chrom_3.shape)

 

Thanks in advance!

0

• Official comment

  

  Simranjit Kaur

  • Gurobi Staff

  November 16, 2025 23:26

  This post is more than three years old. Some information may not be up to date. For current information, please check the Gurobi Documentation or Knowledge Base. If you need more help, please create a new post in the community forum, or try Gurobot, our chatbot interface offering instant, expert-level support.
• 

  Jaromił Najman

  • Gurobi Staff

  November 02, 2022 09:46

  Hi Nahom,

  Why exactly do you need the \(\texttt{chrom_list}\) object? You could just directly pass the objective value to your chrom_3 array.

  
  for i in range(10):
  # update model, solve, return the chromatic number
      m.update()
      m.optimize()
      chrom_num = m.objVal
      print("chromatic number of this graph is ", m.objVal)
      chrom_3 = np.asarray(chrom_num)
      m.reset()
      print(chrom_3.shape)

  If you need the \(\texttt{chrom_list}\), you should define it outside of the loop

  
  chrom_list = []
  for i in range(10):
   # update model, solve, return the chromatic number
      m.update()
      m.optimize()
      chrom_num = m.objVal
      print("chromatic number of this graph is ", m.objVal)
      chrom_list.append(chrom_num)
      chrom_3 = np.asarray(chrom_list[i])
      m.reset()
      print(chrom_3.shape)

  Best regards, 
  Jaromił

  0

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