Can we not solve 2 models in a single python file with Gurobipy?
AnsweredI have been running 2 models, namely m1 and m2.
In one of them, I used constraints like
y=m.addVars(list(product(P,N)),vtype=GRB.BINARY,name='Y'), which is working fine.
and in model 2 named m1, I used
xmtn=m1.addVars(list(product(M,TN)),vtype=GRB.INTEGER,name='xmtn') whis is showing an error saying
"List object not callable".
Kindly help me in this regard.
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Hi,
Could you provide a minimal working example to reproduce the issue? In this case, one would at least need the definition of \(\texttt{P, N, M, TN}\).
Best regards,
Jaromił0 -
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Hi @Jaromil.... Here P, N , M, TN are the list consists of natural integer numbers
For example
P=[i for i in range(5)]...
Like wise all the lists...0 -
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It's hard to help without a working code example that reproduces the issue. There is something else in your code that is contributing to the error. My best guess is that you assigned a list object to a Python variable named \( \texttt{list} \) or \( \texttt{product} \), which would overwrite the \( \texttt{list} \) built-in or \( \texttt{itertools.product} \). The following code runs fine:
import gurobipy as gp
from gurobipy import GRB
from itertools import product
M = [i for i in range(5)]
TN = [i for i in range(10)]
m1 = gp.Model()
xmtn = m1.addVars(list(product(M, TN)), vtype=GRB.INTEGER, name='xmtn')By the way, the above code can be simplified (and made more efficient) as follows:
import gurobipy as gp
from gurobipy import GRB
m1 = gp.Model()
xmtn = m1.addVars(5, 10, vtype=GRB.INTEGER, name='xmtn')0 -
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Thank You so much Eli Towle. The alternative method has resolved my problem. Thanks again.
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