Problem with tuple and floar addition

Answered

Leon Breukel

September 17, 2021 16:23

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Hello guys i have a little problen with the following code:

 

I want to add the product from alpha and better to the costs c but i dont know how to convert it to a float? i would really appreciate your help!

from gurobipy import *

I,M = multidict({1:[(400,340,500)], 2:[(650,200,400)], 3:[(300,600,500)], 4:[(500,600,600)]})

J,Max,Min = multidict({1:[3000,200], 2:[3000,200],3:[3000,200], 4:[3000,200]})


d = {(1,'Butanol'):((0,0,0),(80,70,90),(80,70,90),(100,110,90)),   (1,'Biodiesel'):((0,0,0),(90,80,100),(95,85,75),(85,75,95)),   
     (2,'Butanol'):((0,0,0),(280,270,290),(280,300,290),(280,260,270)),  (2,'Biodiesel'):((0,0,0),(120,130,110),(150,170,160),(110,120,130)),   
     (3,'Butanol'):((0,0,0),(240,250,260),(230,250,240),(240,250,260)),  (3,'Biodiesel'):((0,0,0),(140,150,130),(150,140,130),(120,150,110)),   
     (4,'Butanol'):((0,0,0),(180,170,160),(130,120,140),(150,160,170)),  (4,'Biodiesel'):((0,0,0),(80,70,60),(60,70,50),(80,70,60)),    
     (5,'Butanol'):((0,0,0),(180,170,190),(180,170,190),(180,170,190)),  (5,'Biodiesel'):((0,0,0),(80,70,90),(80,100,90),(100,80,90)) 
     }
K = set([k for (k,p) in d])


P = set([p for (k,p) in d])




produce = {1:['switch'], 2:['seed'], 3:['salz'], 4:['süß']}

alpha = {('Butanol', 'switch'):0.189,('Biodiesel', 'switch'):0,('Butanol', 'seed'):0.189,('Biodiesel', 'seed'):0,('Butanol', 'salz'):0.078,('Biodiesel', 'salz'):0.24125,('Butanol', 'süß'):0.078,('Biodiesel', 'süß'):0.24125}

beta = {('Butanol', 'switch'):1.233,('Biodiesel', 'switch'):0,('Butanol', 'seed'):1.233,('Biodiesel', 'seed'):0,('Butanol', 'salz'):2.044,('Biodiesel', 'salz'):(-2,846),('Butanol', 'süß'):2.0444,('Biodiesel', 'süß'):(-2,846)}

weight_bio = {'switch':0.00175, 'seed':0.00175, 'salz':0.00175, 'süß':0.00175}
cost_bio = {(1,1):4,  (1,2):6, (1,3):9, (1,4):3,
        (2,1):5,  (2,2):4, (2,3):7, (2,4):5,
        (3,1):6,  (3,2):8, (3,3):4, (3,4):6,
        (4,1):8,  (4,2):5, (4,3):3, (4,4):6,
        (5,1):10, (5,2):8, (5,3):4, (5,4):9
        }

c_bio = {}
for i in I:
    for j in J:
        for q in produce[i]:
            for p in P:
                c_bio[i, j, q] = cost_bio[i,j] * weight_bio[q] +(beta[p,q] *alpha[p,q])

1

• Official comment

  

  Simranjit Kaur

  • Gurobi Staff

  June 23, 2025 02:47 Edited

  This post is more than three years old. Some information may not be up to date. For current information, please check the Gurobi Documentation or Knowledge Base. If you need more help, please create a new post in the community forum. Or why not try our AI Gurobot?.
• 

  Jaromił Najman

  • Gurobi Staff

  September 20, 2021 07:45

  Hi Leon,

  Please note that this is not really a Gurobi related question.

  The values of \(\texttt{('Biodiesel','salz')}\) and \(\texttt{('Biodiesel,'süß')}\) are given as pairs and not floats (note the comma \((-2, 846)\)). These should probably read

  ('Biodiesel', 'salz'):(-2.846), [...], ('Biodiesel', 'süß'):(-2.846)

  Best regards,
  Jaromił

  0

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