comparison of the values of two dictionnaries

Answered

Geoffrey James Kameni Tchokode

• August 26, 2022 12:34

Hi,

I want to compare the values of two given dict and print an output if they are identic. But it gives me only "zero" for all cases, although some elements are identic.

Something goes wrong by the iteration, but i can't fix it.

Thks for support

Geoffrey

Aisle_arct={1:['m','b','p','d','g'], 2:['y','i','a','e','h'], 3:['n','q','c','f','j']}
Order={1:['h', 'p', 'g', 'j', 'm', 'i', 'c', 'a', 'b', 'n', 'f', 'q', 'd'], 2:['f', 'y', 'e', 'q', 'a', 'c'], 3: ['c'], 4: ['a', 'h', 'c', 'i']}

dvar={}
for i in Order:
    for z in Order[i]:
        for k in Aisle_arct:
            for j in Aisle_arct[k]:
                if (z==j):
                    dvar[i,k]=L
                else:
                    dvar[i,k]=0

print(dvar)

Output

{(1, 1): 0, (1, 2): 0, (1, 3): 0, (2, 1): 0, (2, 2): 0, (2, 3): 0, (3, 1): 0, (3, 2): 0, (3, 3): 0, (4, 1): 0, (4, 2): 0, (4, 3): 0}

 

0

• 

  Jaromił Najman

  Gurobi Staff

  • August 26, 2022 14:56

  Please note that this is not a Gurobi question but a general Python question and should be and should be rather posted in a Python forum instead of here.

  Anyway, you are overwriting your \(\texttt{dvar}\) values with \(0\). For example, when you check for \(\texttt{Order[1][4]}\) and \(\texttt{Aisle_arct[1][0]}\), you will temporarily have a value of \(\texttt{dvar[1,1]=L}\). However, the last comparison for \(\texttt{i=1, k=1}\) is  \(\texttt{Order[1][12]='d'}\) \(\neq\) \(\texttt{'g'=Aisle_arct[1][4]}\) and thus you get \(\texttt{dvar[1,1]=0}\).

  I don't know what you want to do with the \(\texttt{dvar}\) dict, but one way (probably not the most pythonic one) to get only the matching characters would be

  dvar={}
  for i in Order:
      for k in Aisle_arct:
          dvar[i,k] = []
          for z in Order[i]:
              for j in Aisle_arct[k]:
                  if (z==j):
                      dvar[i,k].append(z)
  
  print(dvar)

  Best regards, 
  Jaromił

  0

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