Type Error Objective Function

回答済み

Abbigail Stockman

2023年02月21日 01:49

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Hi! I am having this error come up when I run my code and I am unsure as to why. Can I get help fixing this?

error: TypeError: 'int' object is not callable

code:

import math
from gurobipy import GRB,Model

x = [0.1, 0.15, 0.35, 0.5, 0.65, 0.85, 0.95]
y = [2.5, 2.2, 1.8, 1.5, 1.3, 0.9, 0.4]

m = Model()
# Set parameters
m.setParam('OutputFlag',True)
# Add variables
z1 = m.addVar(name='z1') 
z2 = m.addVar(name='z2') 
z3 = m.addVar(name='z3') 
z4 = m.addVar(name='z4') 
z5 = m.addVar(name='z5') 
z6 = m.addVar(name='z6') 
z7 = m.addVar(name='z7') 
a = m.addVar(name='a') 
b = m.addVar(name='b') 
c = m.addVar(name='c')   
# Add constraints
m.addConstr(2.5-(a+(b*(0.1**3))+ c*math.log(0.1)) <= z1, name='c1')
m.addConstr(-(2.5-(a+(b*(0.1**3))+ c*math.log(0.1))) <= z1, name='c2')
m.addConstr(2.2-(a+(b*(0.15**3))+ c*math.log(0.15)) <= z2 ,name='c3')
m.addConstr(-(2.2-(a+(b*(0.15**3))+ c*math.log(0.15))) <= z2, name='c4')
m.addConstr(1.8-(a+(b*(0.35**3))+ c*math.log(0.35)) <= z3 ,name='c5')
m.addConstr(-(1.8-(a+(b*(0.35**3))+ c*math.log(0.35))) <= z3, name='c6')
m.addConstr(1.5-(a+(b*(0.5**3))+ c*math.log(0.5)) <= z4, name='c7')
m.addConstr(-(1.5-(a+(b*(0.5**3))+ c*math.log(0.5))) <= z4, name='c8')
m.addConstr(1.3-(a+(b*(0.65**3))+ c*math.log(0.65)) <= z5 ,name='c9')
m.addConstr(-(1.3-(a+(b*(0.65**3))+ c*math.log(0.65))) <= z5, name='c10')
m.addConstr(0.9-(a+(b*(0.85**3))+ c*math.log(0.85)) <= z6 ,name='c11')
m.addConstr(-(0.9-(a+(b*(0.85**3))+ c*math.log(0.85))) <= z6, name='c12')
m.addConstr(0.4-(a+(b*(0.95**3))+ c*math.log(0.95)) <= z7 ,name='c13')
m.addConstr(-(0.4-(a+(b*(0.95**3))+ c*math.log(0.95))) <= z7, name='c14')
# Set the objective
m.setObjective((1/7)*(z1 + z2 + z3 + z4 + z5 + z6 + z7), GRB.MINIMIZE())
m.optimize()

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• 

  Riley Clement

  • Gurobi Staff

  2023年02月21日 02:03 編集済み

  Hi Abbigail,

  You'll want to remove the brackets from GRB.MINIMIZE, it's not a function, and is just an integer in disguise. (Try print(GRB.MINIMIZE) for example).

  - Riley

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  Abbigail Stockman

  2023年02月21日 02:16

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  thank you so much!

   

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