getVarByName c++

回答済み

zakarya guettatfi

2023年05月18日 09:12 編集済み

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After optimizing a model, I need to take a specific value "x1" from solutions

Using c++

m1.getVarByName("x1")

I got this error

: error: ambiguous overload for ‘operator<<’ (operand types are ‘std::ostream’ {aka ‘std::basic_ostream<char>’} and ‘GRBVar’)
         cout << m1.getVarByName("x1") << endl;

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I use m1.get(x[i]) and I got this error

lib/gurobi_c++.h:772:18: note: candidate: ‘std::__cxx11::string* GRBModel::get(GRB_StringAttr, const GRBGenConstr*, int)’
     std::string* get(GRB_StringAttr attr, const GRBGenConstr* xgenconstrs, int len);

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Is that any way to extract "x1" from solutions

関連

• C++

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  David Torres Sanchez

  • Gurobi Staff

  2023年05月18日 15:21 編集済み

  Hi Zakarya,

  Using \(\texttt{getVarByName("x1")}\) will return a GRBVar.
  You cannot print this to stdout.
  You can, however, print its value or its name as shown in our mip1_c++.cpp example.

  Cheers, 
  David

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