How can I add a parameter into the the constraint?

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merve özer

2021年01月25日 18:50 編集済み

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I am trying to solve the following generalized assignment problem in Gurobi. I managed to solve the problem when bij is =1 which is a simple assignment problem. Now I am trying to solve the generalized assignment problem when bij (capacity consumption values) has different values, but I got stuck in adding this bij parameter into the constraints. I think, I should firstly define bij (but not quite sure how to), then put into the Resource1 and Resource2 constraints, something like that,  but it did not work. 

Resource1 = m.addConstrs((x.sum('Resource1', '*')*b(i,j) for i in I for j in J<=5 ), 'Resource1')

 

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  Simranjit Kaur

  • Gurobi Staff

  2025年06月23日 03:00 編集済み

  This post is more than three years old. Some information may not be up to date. For current information, please check the Gurobi Documentation or Knowledge Base. If you need more help, please create a new post in the community forum. Or why not try our AI Gurobot?.
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  Jaromił Najman

  • Gurobi Staff

  2021年01月26日 13:58 編集済み

  Hi Merve,

  You could use the quicksum function to model these 2 constraints as

  Resource1 = m.addConstr( quicksum( x['Resource1',i] * mh['Resource1',i] for i in I ) <= 5 , name="Resource1" )
  Resource2 = m.addConstr( quicksum( x['Resource2',i] * mh['Resource2',i] for i in I ) <= 12 , name="Resource2" )

  You can access the values of \(\texttt{mh}\) via the \(\texttt{[]}\) operator and the corresponding key given in the \(\texttt{matching}\) list. Thus, \(\texttt{mh['Resource1‘,'item1‘]}\) provides the integer 3.

  Best regards,
  Jaromił

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  merve özer

  2021年01月26日 15:57

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  This is great! I obtained exactly what I wanted. Thank you very much.

  Kind regards,

  Merve

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