Problem with tuple and floar addition

回答済み

Leon Breukel

• 2021年09月17日 16:23

Hello guys i have a little problen with the following code:

 

I want to add the product from alpha and better to the costs c but i dont know how to convert it to a float? i would really appreciate your help!

from gurobipy import *

I,M = multidict({1:[(400,340,500)], 2:[(650,200,400)], 3:[(300,600,500)], 4:[(500,600,600)]})

J,Max,Min = multidict({1:[3000,200], 2:[3000,200],3:[3000,200], 4:[3000,200]})


d = {(1,'Butanol'):((0,0,0),(80,70,90),(80,70,90),(100,110,90)),   (1,'Biodiesel'):((0,0,0),(90,80,100),(95,85,75),(85,75,95)),   
     (2,'Butanol'):((0,0,0),(280,270,290),(280,300,290),(280,260,270)),  (2,'Biodiesel'):((0,0,0),(120,130,110),(150,170,160),(110,120,130)),   
     (3,'Butanol'):((0,0,0),(240,250,260),(230,250,240),(240,250,260)),  (3,'Biodiesel'):((0,0,0),(140,150,130),(150,140,130),(120,150,110)),   
     (4,'Butanol'):((0,0,0),(180,170,160),(130,120,140),(150,160,170)),  (4,'Biodiesel'):((0,0,0),(80,70,60),(60,70,50),(80,70,60)),    
     (5,'Butanol'):((0,0,0),(180,170,190),(180,170,190),(180,170,190)),  (5,'Biodiesel'):((0,0,0),(80,70,90),(80,100,90),(100,80,90)) 
     }
K = set([k for (k,p) in d])


P = set([p for (k,p) in d])




produce = {1:['switch'], 2:['seed'], 3:['salz'], 4:['süß']}

alpha = {('Butanol', 'switch'):0.189,('Biodiesel', 'switch'):0,('Butanol', 'seed'):0.189,('Biodiesel', 'seed'):0,('Butanol', 'salz'):0.078,('Biodiesel', 'salz'):0.24125,('Butanol', 'süß'):0.078,('Biodiesel', 'süß'):0.24125}

beta = {('Butanol', 'switch'):1.233,('Biodiesel', 'switch'):0,('Butanol', 'seed'):1.233,('Biodiesel', 'seed'):0,('Butanol', 'salz'):2.044,('Biodiesel', 'salz'):(-2,846),('Butanol', 'süß'):2.0444,('Biodiesel', 'süß'):(-2,846)}

weight_bio = {'switch':0.00175, 'seed':0.00175, 'salz':0.00175, 'süß':0.00175}
cost_bio = {(1,1):4,  (1,2):6, (1,3):9, (1,4):3,
        (2,1):5,  (2,2):4, (2,3):7, (2,4):5,
        (3,1):6,  (3,2):8, (3,3):4, (3,4):6,
        (4,1):8,  (4,2):5, (4,3):3, (4,4):6,
        (5,1):10, (5,2):8, (5,3):4, (5,4):9
        }

c_bio = {}
for i in I:
    for j in J:
        for q in produce[i]:
            for p in P:
                c_bio[i, j, q] = cost_bio[i,j] * weight_bio[q] +(beta[p,q] *alpha[p,q])

1

• 正式なコメント

  

  Simranjit Kaur

  Gurobi Staff

  • 2024年12月06日 00:25

  This post is more than three years old. Some information may not be up to date. For current information, please check the Gurobi Documentation or Knowledge Base. If you need more help, please create a new post in the community forum. Or why not try our AI Gurobot?.
• 

  Jaromił Najman

  Gurobi Staff

  • 2021年09月20日 07:45

  Hi Leon,

  Please note that this is not really a Gurobi related question.

  The values of \(\texttt{('Biodiesel','salz')}\) and \(\texttt{('Biodiesel,'süß')}\) are given as pairs and not floats (note the comma \((-2, 846)\)). These should probably read

  ('Biodiesel', 'salz'):(-2.846), [...], ('Biodiesel', 'süß'):(-2.846)

  Best regards,
  Jaromił

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