How to add equation containing decision variable into an array.

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Thunwa Wanphian

2022年06月14日 08:29

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I got a problem to store the equation containing the decision variable into an array.

Here, This is my code and noted that y[j,k] is my binary decision variable. 

Time_span = 16
Expo_noise_matrix = range(1,Time_span+1)
Times = range(1,Time_span+1)

for k in Times:
    Expo_noise_matrix[k] = ((70*y[1,k]+60*y[2,k]+80*y[3,k])*(1-((-1+y[1,k]+y[2,k]+y[3,k])*0.2)))

The error showed this,

      3 for k in Times:
----> 4     Expo_noise_matrix[k] = ((70*y[1,k]+60*y[2,k]+80*y[3,k])*(1-((-1+y[1,k]+y[2,k]+y[3,k])*0.2)))

TypeError: 'range' object does not support item assignment

I need to store those decision variable equations in array to call and calculate the objective function next.

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• 正式なコメント

  

  Simranjit Kaur

  • Gurobi Staff

  2025年11月16日 23:34

  This post is more than three years old. Some information may not be up to date. For current information, please check the Gurobi Documentation or Knowledge Base. If you need more help, please create a new post in the community forum, or try Gurobot, our chatbot interface offering instant, expert-level support.
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  Jaromił Najman

  • Gurobi Staff

  2022年06月15日 07:38

  In your code \(\texttt{Expo_noise_matrix}\) is a range object and thus, you cannot assign values to it.

  You should rather use a dictionary for \(\texttt{Expo_noise_matrix}\).

  Time_span = 16
  Expo_noise_matrix = {}
  Times = range(1,Time_span+1)
  
  for k in Times:
      Expo_noise_matrix[k] = ((70*y[1,k]+60*y[2,k]+80*y[3,k])*(1-((-1+y[1,k]+y[2,k]+y[3,k])*0.2)))

  Best regards, 
  Jaromił

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  Thunwa Wanphian

  2022年06月15日 07:54

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  Dear: Jaromił

  It's work now, thank you :).

  Best regards,

  Thunwa.

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