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How to deal with a fraction of binary decision variables

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  • Jonasz Staszek
    • Community Moderator Community Moderator
    • Gurobi-versary
    • Thought Leader
    • First Question

    Dear Simon,

    the reason for the lower bound being set to \( x^L > 0 \) in the case you mention is to avoid  \( x \) assuming the value of \( 0 \).

    If you also need to include the case of negative values of \( x \), you may want to use indicator constraints (see here and here). They will allow you to model two cases: one for \( x > 0 \) and the other for \( x < 0 \). If you need more guidance, let me know.

    Best regards,
    Jonasz

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